Factors that make NCERT Solutions the Perfect Study Material for CBSE Students |
Posted: September 20, 2019 |
Established on 1 September 1961, the National Council of Educational Research and Training (NCERT) is an autonomous organization of the Government of India. NCERT provides the curriculum guidelines for the Central Board of Secondary Education (CBSE), the most popular board for secondary education in India. NCERT is also the body responsible for its books which are prescribed nationwide in schools. The days before exams for all the class 10 students are pretty hectic with full of preparation and revisions. Students should practice throughout the year but the time just before the exam is most crucial as they need to retain all the information to ensure they do well. Knowing as such the latest pattern of examination, the types of questions, weightage of these questions in CBSE board, division of marks for various units in a subject, etc can help students ace the examination with ease. How following NCERT Books help you score well NCERT textbooks are designed to make learning enjoyable and stress-free. The books seek to discourage students from following the rote method of learning by integrating it with knowledge of life outside school. It also seeks to make exams less stressful by nurturing the learning abilities of students at all stages. As such, these textbooks are the primary source of information for exam preparation. Also, CBSE sample papers for class 10 go a long way in helping students prepare well for their main examinations. It is designed in a way similar to the pattern followed in the main exam and as such the sample papers are perfect for improving knowledge and understanding of any subject. Pattern for CBSE Class X exam 2019
CBSE Class 10 Mathematics Sample Question The marking schemes issued by CBSE gives the students a good idea about the allocation of marks and criteria for answering correctly in the board examinations. Find the value(s) of k for which the equation x2 + 5kx + 16 = 0 has real and equal roots. Sol. For roots to be real and equal, b2 – 4ac = 0 ⇒ (5k)2 – 4 × 1 × 16 = 0 Therefore k=+-8/5
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